Hi there,
I actually don't think you actually need to use ameliabind() here. The
amelia output already has all of the datasets together. It might help us to
know what is it that you want to accomplish with ameliabind() in this case.
Cheers,
Matt
On Thu, Nov 12, 2015 at 10:11 PM, W. D. <WD(a)a7h.com> wrote:
At 06:47 11/11/2015, Matt Blackwell wrote:
Hi there,Â
The 5 imputed datasets are actually contained in the DataImputed object
and you can
access each imputed dataset like so:
DataImputed$imputations[[1]]
DataImputed$imputations[[2]]
And so on. ameliabind() will merge the output of two amelia() calls into
1 so that
if each had 5 imputed datasets, then the binded object will have
10.Â
Thanks for the clue, Matt.
However when I run:
DataImputedAll <- ameliabind(DataImputed$imputations[[1]],
DataImputed$imputations[[2]], DataImputed$imputations[[3]],
DataImputed$imputations[[4]], DataImputed$imputations[[5]])
It rudely spits out:
"All arguments must be amelia output."
When searching for that particular error, there isn't anything
useful.
What do you suggest?
Thanks for your assistance!
Hope that helps!
Cheers,
Matt
~~~~~~~~~~~
Matthew Blackwell
Assistant Professor of Government
Harvard University
url: <http://www.mattblackwell.org>http://www.mattblackwell.orgÂ
<http://www.mattblackwell.xn--org-kla>
On Wed, Nov 11, 2015 at 1:14 AM, W. D. <<mailto:WD@a7h.com>WD@a7h.com>
wrote:
If 5 sets of data are generated using a command
like
this:
DataImputed <- amelia(x=GroupData,incheck=TRUE)
What would be the names of the 5 sets of data in order
to use ameliabind?
DataImputedAll <- ameliabind(set1?, set2?, set3?, set4?, set5?)
There seem to be a dearth of examples online.
Thanks for your help.
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